| 发表于:2007-08-14 09:11:131楼 得分:10 |
public type mystruct szlicense as string * 16 identifier as string * 10 end type dim match(19) as mystruct, i as integer for i = 0 to 19 match(i).szlicense = string(16, chr(0)) match(i).identifier = string(10, chr(0)) next i | | |
|