| 发表于:2007-06-07 08:45:0010楼 得分:0 |
public function trapez(byval a!, byval b!, byval n&) as single 'b、a分别为积分上下限,n为等分数 dim sum!, h!, x!, i&,f1!,f2! h = (b - a) / n f1=f(a) sum=0 for i = 1 to n x = a + i * h f2=f(x) sum = sum + (f1+f2)/2*h f1=f2 next i trapez = sum end function | | |
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