| 发表于:2007-03-29 08:12:412楼 得分:0 |
1. zyg0给出了最佳答案 2. 楼主的代码修改一下也行: dim lstr as string, str1 as string '注:dim lstr, str1 as sting等价于dim lst as variant, str1 as string, 存在问题 dim i as integer, j as integer lstr= "abcde#fghijk " str1= " " i=1 j=len(lstr) do while i <=j if mid(lstr,i,1) <> "# " then str1=str1+mid(lstr,i,1) end if i=i+1 loop | | |
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