| 发表于：2007-01-30 15:28:12 楼主 |
public class simplethreads {
//display a message, preceded by the name of the current thread
static void threadmessage（string message) {
string threadname = thread.currentthread（).getname（);
system.out.format（ "%s: %s%n ", threadname, message);
}
private static class messageloop implements runnable {
public void run（) {
string importantinfo[] = {
"mares eat oats ",
"does eat oats ",
"little lambs eat ivy ",
"a kid will eat ivy too "
};
try {
for （int i = 0; i < importantinfo.length; i++) {
//pause for 4 seconds
thread.sleep（4000);
//print a message
threadmessage（importantinfo[i]);
}
} catch （interruptedexception e) {
threadmessage（ "i wasn 't done! ");
}
}
}
public static void main（string args[]) throws interruptedexception {
//delay, in milliseconds before we interrupt messageloop
//thread （default one hour).
long patience = 1000 * 60 * 60;
//if command line argument present, gives patience in seconds.
if （args.length > 0) {
try {
patience = long.parselong（args[0]) * 1000;
} catch （numberformatexception e) {
system.err.println（ "argument must be an integer. ");
system.exit（1);
}
}
threadmessage（ "starting messageloop thread ");
long starttime = system.currenttimemillis（);
thread t = new thread（new messageloop（));
t.start（);
threadmessage（ "waiting for messageloop thread to finish ");
//loop until messageloop thread exits
while （t.isalive（)) {
threadmessage（ "still waiting... ");
//wait maximum of 1 second for messageloop thread to
//finish.
t.join（1000);
if （（（system.currenttimemillis（) - starttime) > patience) &&
t.isalive（)) {
threadmessage（ "tired of waiting! ");
t.interrupt（);
//shouldn 't be long now -- wait indefinitely
t.join（);
}
}
threadmessage（ "finally! ");
}
}
１，这就一个文件可编译后怎么出来三个class呀？？？
而它只有一个内部类。
２，此段程序中如何在运行时通过string [] args来输入信息？？？
３，此段程序中怎么来体现中方法interrupt的调用？？？
４， |
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